The value of ( n × l × m ) for the last electron entered in K is

K: [ A r ] 4 s 1 . Here, n = 4 , l = 0 , m = 0 . Thus, n × l × m = 4 × 0 × 0 = 0 .

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The value of $(n \times l \times m)$ for the last electron entered in K is

Answer:

Solution:

K: $[A r] 4 s^{1}$ .

Here, $n = 4$ , $l = 0$ , $m = 0$ .

Thus, $n \times l \times m = 4 \times 0 \times 0 = 0$ .

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Quantum Numbers

⏱ 2mℹ️ Source: QB

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