The orbital angular momentum of an electron in 3 s orbital is xh 2 π . The value of x is (nearest integer)

The orbital angular momentum = h 2 π l l + 1 For 3 s -electron, l = 0 . ∴ The orbital angular momentum = h 2 π 0 0 + 1 = 0 zero

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ChemistryAtomic StructureSchrödinger's EquationEasy2 minPYQ_2023

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The orbital angular momentum of an electron in $3 s$ orbital is $\frac{xh}{2 π}$ . The value of $x$ is (nearest integer)

Answer:

Solution:

The orbital angular momentum
$= \frac{h}{2 π} \sqrt{l (l + 1)}$

For $3 s$ -electron, $l = 0$ .

$∴$ The orbital angular momentum
$= \frac{h}{2 π} \sqrt{0 (0 + 1)}$
$= 0 (zero)$

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Schrödinger's Equation

⏱ 2mℹ️ Source: PYQ_2023

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