Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

When a transition of electron in $H e^{+}$ takes place from $n_{2}$ to $n_{1}$ then wave number in terms of Rydberg constant R will be
(Given $n_{1} + n_{2} = 4, n_{2} - n_{1} = 2)$

Options:

Answer:

Solution:

$n_{1} + n_{2} = 4$

$n_{2} - n_{1} = 2$

$2 n_{2} = 6$

$n_{2} = 3$

$n_{1} = 1$

$3 \to 1$

$\bar{ν} = \frac{1}{λ}$
$= R Z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$
$= R \times 2^{2} (\frac{1}{1^{2}} - \frac{1}{3^{2}})$
$= 4 R \times \frac{8}{9}$
$= \frac{32 R}{9}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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