Chemistry - Atomic Structure Question with Solution | TestHub

Energy of an atom when n = 1

${\mathrm{E}}_1=-\frac{1312}{(1{)}^2}=-1312\text{ kJ mo}{\text{l}}^{-1}$

Similarly energy when$\mathrm{n}=3,\left({\mathrm{E}}_3\right)=-\frac{1312}{(3{)}^2}$

$=-145.7\text{ kJ mo}{\text{l}}^{-1}$

The energy absorbed when an electron jumps from$\mathrm{n}=1$to$\mathrm{n}=3$

${\mathrm{E}}_3-{\mathrm{E}}_1=-145.7-\left(-1312\right)=1166.3\text{ kJ mo}{\text{l}}^{-1}$

$=\frac{1166.3}{6.023\times 10^{23}}=193.6\times 10^{-23}\mathrm{k}\mathrm{J}$

$=193.6\times 10^{-20}\mathrm{J}\left[\text{1 Joule}=10^7\text{ ergs}\right]$

$193.6\times 10^{-13}\mathrm{e}\mathrm{r}\mathrm{g}\mathrm{s}=0.1936\times 10^{-10}\mathrm{e}\mathrm{r}\mathrm{g}\mathrm{s}$