The radius of the first orbit of hydrogen atom is 0.52 × 1 0 - 8 cm. The radius of the first orbit of helium atom is

r n = n 2 Z 0.52 × 1 0 - 8 cm For H-atom Z = 1 , n = 1, r 1 = 0.52 × 1 0 - 8 cm For He atom, n = 1, Z = 2, r 1 = 1 2 × 0.5 × 1 0 - 8 cm = 0.26 × 1 0 - 8 cm

Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The radius of the first orbit of hydrogen atom is $0.52 \times 1 0^{- 8}$ cm. The radius of the first orbit of helium atom is

Options:

Answer:

Solution:

$r_{n} = \frac{n^{2}}{Z} (0.52 \times 1 0^{- 8} cm)$
For H-atom $Z = 1$ , n = 1, $r_{1} = 0.52 \times 1 0^{- 8} cm$
For He atom, n = 1, Z = 2,
$r_{1} = \frac{1}{2} \times 0.5 \times 1 0^{- 8}$ cm
$= 0.26 \times 1 0^{- 8}$ cm

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...