Chemistry - Atomic Structure Question with Solution | TestHub

$\begin{array}{l}{\text{E}}_{\text{n}}=-13.6\times \frac{{\text{Z}}^2}{{\text{n}}^2}\text{e}\text{V}\\ \text{Z}=1\text{f}\text{o}\text{r}\text{H}.\end{array}$

${\text{E}}_{\text{n}}=\frac{-\text{13.6}}{{\text{n}}^2}\text{eV}$

Where$\text{n}=2\Rightarrow {\text{E}}_2=-\text{3.40 eV}$