If the radius of H is 0.53 A ~ … , then what will be the radius of 3 Li 2 + ?

Radius of orbit = z n 2 a o ( a o = 0.529 A ) Radius of H = 1 ( 1 ) 2 × 0.529 A = 0.53 A Thus, the radius of 3 Li 2 + will be = 3 ( 1 ) 2 × 0.529 = 0.17 A ~ …

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ChemistryAtomic StructureBohr's Atomic ModelMedium2 minPYQ_2012

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If the radius of $H$ is $0.53 \tilde{A} \dots$ , then what will be the radius of $_{3} Li^{2 +}$ ?

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Solution:

Radius of orbit $= \frac{n ^{2} a _{o}}{z} (a_{o} = 0.529 A)$ Radius of $H = \frac{( 1 ) ^{2} \times 0.529 A}{1} = 0.53 A$ Thus, the radius of $_{3} Li^{2 +}$ will be $= \frac{( 1 ) ^{2} \times 0.529}{3} = 0.17 \tilde{A} \dots$

Stream:BITSATSubject:ChemistryTopic:Atomic StructureSubtopic:Bohr's Atomic Model

⏱ 2mℹ️ Source: PYQ_2012

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