Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

3. Moles of C₆H₆ = $\frac{156}{78}=2$

Moles of X = $2\times 0.5$

Moles of Y = $2\times 0.5\times 0.4$

Moles of Q = $2\times 0.5\times 0.4\times 0.5$

Moles of R = $2\times 0.5\times 0.4\times 0.5\times 1=0.20$

Mass of R = $0.20\times 180$ (Molecular mass of Aspirin = 180) = $34$ gram

4. Moles of P = $2\times 0.5\times 0.4\times 1$

Moles of S = $2\times 0.5\times 0.4\times 1\times 0.5=0.20$

Mass of S = $0.20\times 212$ (Molecular mass of C₁₄H₁₂O₂) = $42.4$ gram