Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

The conversion of n-hexane to benzene involves cyclization and dehydrogenation, also known as aromatization. This process requires a catalyst that can facilitate these reactions at high temperatures.

The correct catalyst for this conversion is a mixture of chromium(III) oxide and aluminum oxide (${\mathrm{Cr}}_2{\mathrm{O}}_3-{\mathrm{Al}}_2{\mathrm{O}}_3$). The chromium oxide acts as the active catalytic site, promoting dehydrogenation, while the alumina provides a high surface area for the reaction to occur.

AlCl₃ is a Lewis acid catalyst used in Friedel-Crafts reactions, not aromatization of alkanes. MnO₂ is an oxidizing agent, and SiO₂-Al₂O₃ is a cracking catalyst.

Therefore, the answer is C.

$$\mathrm{n}-\mathrm{hexane}\underset{{\mathrm{Cr}}_2{\mathrm{O}}_3-{\mathrm{Al}}_2{\mathrm{O}}_3}{\overset{\Delta ,\mathrm{high}\mathrm{pressure}}{\to }}\mathrm{benzene}+{\mathrm{H}}_2$$