Phenol Zinc distillation ( A ) Conc. HNO 3 Conc. H 2 SO 4 at 6 0 ∘ C ( B ) Sn / HCl − OH ( C ) In the above reaction , compounds (A) , (B) and (C) are:

Question

Phenol Zinc distillation ​ ( A ) Conc. HNO 3 ​ Conc. H 2 ​ SO 4 ​ at 6 0 ∘ C ​ ​ ( B ) Sn / HCl − OH ​ ( C ) In the above reaction , compounds (A) , (B) and (C) are:

TestHub · Accepted Answer

Step - 1 :Formationn of benzene(A)

Phenol undergoes zinc distillation, which is a reduction reaction, to form benzene.

$C_{6} H_{5} O H + Z n d i s t i ll a t i o n C_{6} H_{6} (A) + Z n O$

Step 2: Formation of Nitrobenzene (B)

Benzene (A) undergoes nitration using a mixture of concentrated nitric acid and concentrated sulfuric acid at $6 0^{\circ} C$ to form nitrobenzene.

$C_{6} H_{6} (A) + H N O_{3} H_{2} S O_{4}, 6 0^{\circ} C C_{6} H_{5} N O_{2} (B) + H_{2} O$

Step -3: Formation of Aniline(C)

Nitrobenzene (B) is reduced by tin and concentrated hydrochloric acid to form aniline (phenylamine). The intermediate anilinium salt is treated with a base (OH^_) to liberate the free amine.

$C_{6} H_{5} N O_{2} (B) + 3 S n + 6 H Cl C_{6} H_{5} N H_{2} (C) + 3 S n C l_{2} + 2 H_{2} O$

Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

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