M e C ≡ C - C O C l → H 2 + L i n d l a r ' s catalyst A The product 'A' is

Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

ChemistryAromatic HydrocarbonMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

$M e C \equiv C - C O C l \overset{H_{2} + {L i n d l a r}^{'} s catalyst}{\to} (A)$
The product 'A' is

Answer:

Solution:

Lindlar's catalyst reduces $(C \equiv C)$ to $(C = C)$ in syn (cis) addition and simultaneously reduces $(- C O C l)$ group to $(- C H O)$ group.

Stream:NTA_ABHYASSubject:ChemistryTopic:Aromatic HydrocarbonSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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