Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

$\left[\text{P}\right]\stackrel{{\text{Br}}_2}{\to }{\text{C}}_2{\text{H}}_4{\text{Br}}_2\stackrel{{\text{NaNH}}_2}{\to }\text{Q}\stackrel{20{\text{\% H}}_2{\text{SO}}_4}{\to }\text{R}\stackrel{\text{ZnHg/HCl}}{\to }\text{S}$

As 'P' undergoes addition reaction with 1 mole of$\mathrm{B}{\mathrm{r}}_2$it means there is only 1 double bond

So 'P' is${\mathrm{C}}_2{\mathrm{H}}_4\left(\mathrm{C}{\mathrm{H}}_2=\mathrm{C}{\mathrm{H}}_2\right)$and the reaction is as follows


Here P, Q, R and S are ethene, ethyne, ethanal and ethane respectively