Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

${\mathrm{C}}_6{\mathrm{H}}_6+{\mathrm{HNO}}_3\to {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NO}}_2+{\mathrm{H}}_2\mathrm{O}$ $78\mathrm{g}123\mathrm{g}$ Now since $78\mathrm{g}$ of benzene on nitration give $=123\mathrm{g}$ nitrobenzene hence $5\mathrm{g}$ of benzene on nitration give $=\frac{123}{78}\times 5=7.88\mathrm{g}$ nearest answer is (c) i.e. theoritical yield $=7.88\mathrm{g}$