x is number of organic compounds soluble in aq. $HCl$
y is number of organic compounds which give foul smell with $CHC l_{3}$ and alcoholic $KOH$ .
z is number of organic compounds which reacts with $NaN O_{2}$ + $HCl$ (0–5ºC) followed by β-napthol gives coloured dye. Then value of (x + y – z) is :

Question

x is number of organic compounds soluble in aq. $HCl$

y is number of organic compounds which give foul smell with $CHC l_{3}$ and alcoholic $KOH$ .

z is number of organic compounds which reacts with $NaN O_{2}$ + $HCl$ (0–5ºC) followed by β-napthol gives coloured dye. Then value of (x + y – z) is :

TestHub · Accepted Answer

The free amines aniline, methylamine, benzylamine, N-methylaniline and N,N-dimethylaniline dissolve in HCl : x=5. Aniline, methylamine and benzylamine are primary and give carbylamine: y=3. Only aniline forms a stable aromatic diazonium salt and azo dye: z=1. Nitrobenzene and benzamide are excluded. Thus x+y-z=5+3-1=7.

Chemistry - AMINES Question with Solution | TestHub

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