9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100\% yield/conversion) is _______ g. (nearest integer)

Question

TestHub · Accepted Answer

Reaction suggests that 1 mole of aniline give 1 mole of orange dye. $so (mol)_{aniline} = (mole)_{orange dye} \frac{9.3 g}{93 g mol ^{- 1}} = \frac{mass of orange dye}{199 g mol ^{- 1}}$ mass of orange dye $= 19.9 g ≃ 20 g$

Chemistry - AMINES Question with Solution | TestHub

Doubts & Discussion