Chemistry - AMINES Question with Solution | TestHub

milli equivalents of${\text{NH}}_{\text{3}}$= milli equivalents of${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$
milli moles of${\text{NH}}_{\text{3}}\times 1=1\text{N}\times 20\text{ml}$
milli moles of${\text{NH}}_{\text{3}}\text{=}\text{20}$milli moles
$\therefore$mass of$\text{N}=\frac{2\cancel{0}\times 14}{100\cancel{0}}$
$=0.28$
$\therefore \%\text{of}\text{N}=\frac{0.28}{0.4}\times 100=70\%$