Chemistry - AMINES Question with Solution | TestHub

Key Idea : The reagent which is present in smaller quantity is called the limiting reagent and the moles of product depends on it and number of moles $=\frac{\text{ weight }}{\text{ molecular weight }}$ $\begin{array}{ccc}\mathrm{PbO}& 2\mathrm{HCl}⟶& {\mathrm{PbCl}}_2+{\mathrm{H}}_2\mathrm{O}\\ 207.2+16& 2(35.5+1)& 207.2+71\\ =223.2& =73& =278.2\end{array}$ Here, 1 mole of $\mathrm{PbO}$ reacts with 2 moles of $\mathrm{HCl}$, thus $\mathrm{PbO}$ is the limiting reagent $\because 223.2\mathrm{g}$ PbO gives ${\mathrm{PbCl}}_2=278.2\mathrm{g}$ $\therefore 6.5\mathrm{g}\mathrm{PbO}$ will give ${\mathrm{PbCl}}_2$ $\begin{array}{rl}& =\frac{278.2}{223.2}\times 6.5\mathrm{g}\\ & =\frac{278.2\times 6.5}{223.2\times 278.2}\mathrm{mol}\\ & =0.029\mathrm{mol}\end{array}$