Chemistry - ALCOHOL & ETHER Question with Solution | TestHub

ChemistryALCOHOL & ETHERREACTIONS OF ALCOHOLS and ETHERSMedium2 minQB

ChemistryMediumsingle choice

HBr reacts with $CH_{2} = CH - OCH_{3}$ under anhydrous conditions at room temperature to give

Answer:

Solution:

$C H_{2} = C H - OC H_{3} + H B r ⇌ [C H_{3} - C + H - OC H_{3} \leftrightarrow C H_{3} - C H = O + C H_{3}] + B r^{-}$

$[C H_{3} - C + H - OC H_{3} \leftrightarrow C H_{3} - C H = O + C H_{3}] + B r^{-} \to C H_{3} - C H B r - OC H_{3}$

Stream:JEESubject:ChemistryTopic:ALCOHOL & ETHERSubtopic:REACTIONS OF ALCOHOLS and ETHERS

⏱ 2mℹ️ Source: QB

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