Chemistry - ALCOHOL & ETHER Question with Solution | TestHub
Hex-4-ene-2-ol on treatment with PCC gives ' A '. ' A ' on reaction with sodium hypoiodite gives ' B ', which on further heating with soda lime gives ' C '. The compound ' C ' is
Options:
Answer:
Solution:
Question Explanation:
The question involves stepwise transformations of Hex-4-ene-2-ol through oxidation, haloform reaction, and decarboxylation to identify the final hydrocarbon product.
Concept: This question is based on
1. Oxidation of alcohols
2. Haloform reaction
3. Decarboxylation (Soda lime reaction)
Solution:
Hex-4-ene-2-ol is a secondary alcohol. On oxidation with PCC, it forms the corresponding ketone, hex- 4-en-2-one (A).
Compound A contains the CH −CO− group, so with sodium hypoiodite it undergoes the haloform
reaction to give sodium pent-3-enoate (B).
On heating B with soda lime, decarboxylation occurs, removing one carbon atom to form 2-butene.
