Chemistry - ALCOHOL & ETHER Question with Solution | TestHub

The mechanism of this reaction is as follows
${{\text{(CH}}_{\text{3}}\text{)}}_{\text{3}}\text{COH}\text{+}\text{HBr}\rightleftharpoons {{\text{(CH}}_{\text{3}}\text{)}}_{\text{3}}\text{C}\stackrel{\text{+}}{\text{O}}{\text{H}}_{\text{2}}\text{+}{\text{Br}}^{-}$(fast)

Hence, formation on carbocation$(\mathrm{C}{\mathrm{H}}_3{)}_3{\mathrm{C}}^{+}$is slow step (R.D.S.).