Chemistry - ALCOHOL & ETHER Question with Solution | TestHub

In method 1, E2 reaction will takes place and alkene will be formed. While in method 2, substitution${\text{(S}}_{\text{N}}\text{1)}$will takes place and ether will be formed.
${\text{CH}}_{\text{3}}\text{Br}\text{+}\text{t-BuONa}\stackrel{{\text{S}}_{\text{N}}\text{1}}{\to }{\text{t-BuOCH}}_{\text{3}}$