CH 3 CH 2 CH 2 OH → conc . H 2 SO 4 X → Cl 2 , hν Y , X and Y are

CH 3 CH 2 CH 2 OH → conc . H 2 SO 4 CH 3 CH = CH 2 X → Cl 2 , hv Cl − CH 2 − CH = CH 2 Y

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Chemistry - ALCOHOL & ETHER Question with Solution | TestHub

ChemistryALCOHOL & ETHERREACTIONS OF ALCOHOLS and ETHERSEasy2 minPYQ_2020

ChemistryEasysingle choice

${CH}_{3} {CH}_{2} {CH}_{2} OH \overset{conc . H_{2} {SO}_{4}}{\to} X \overset{{Cl}_{2}, hν}{\to} Y$ , X and Y are

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Solution:

${CH}_{3} {CH}_{2} {CH}_{2} OH \overset{conc . H_{2} {SO}_{4}}{\to} \underset{X}{{CH}_{3} CH = {CH}_{2}} \overset{{Cl}_{2}, hv}{\to} \underset{Y}{Cl - {CH}_{2} - CH = {CH}_{2}}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ALCOHOL & ETHERSubtopic:REACTIONS OF ALCOHOLS and ETHERS

⏱ 2mℹ️ Source: PYQ_2020

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