Alcohol → P + I 2 X → Mg , dry ether Y → HCHO Z → H 2 O / H + 2 - methylpropanol In this sequence of reactions, the starting alcohol is

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Alcohols on reaction with phosphorous iodide to give alkyl chloride. The product formed has a halogen atom attached to the same carbon which was attached to the hydroxy group.

The alkyl iodide formed reacts with $Mg$ in presence of dry ether to form Grignard reagent, isopropyl magnesium iodide.

The Grignard reagent on reaction with formaldehyde gives $2 -$ methylpropoxide ion.

$2 -$ methylpropoxide ion on acidic hydrolysis finally gives $2 -$ methylpropanol.

Chemistry - ALCOHOL & ETHER Question with Solution | TestHub

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