In the reaction, C 6 H 5 OH ⟶ NaOH ( A ) 14 0 ∘ C , ( 4 − 7 ) atm CO 2 ( B ) ⟶ HCl ( C ) , the compound (C) is

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Chemistry - ALCOHOL & ETHER Question with Solution | TestHub

ChemistryALCOHOL & ETHERREACTIONS OF ALCOHOLS and ETHERSMedium2 minPYQ_2019

ChemistryMediumsingle choice

In the reaction, $C_{6} H_{5} OH ⟶ NaOH (A)$ $14 0^{\circ} C, (4 - 7) atm CO_{2} (B) ⟶ HCl (C)$ , the compound (C) is

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Solution:

Treatment of sodium salt of phenol with $CO_{2}$ under pressure brings about substitution of the-COOH group for the hydrogen of the ring. This is called as Kolbe's reaction

Stream:VITEEESubject:ChemistryTopic:ALCOHOL & ETHERSubtopic:REACTIONS OF ALCOHOLS and ETHERS

⏱ 2mℹ️ Source: PYQ_2019

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