CHEM_REMOVED - CHEMICAL BONDING Question with Solution | TestHub

CHEM_REMOVEDCHEMICAL BONDINGDipole MomentEasy2 minPYQ_2025

CHEM_REMOVEDEasysingle choice

Arrange the following compounds in increasing order of their dipole moment : $HBr, H_{2} S, NF_{3}$ and $CHCl_{3}$

Answer:

Solution:

$μ_{HBr} = 0.78 D μ_{H_{2} S} = 0.95 D μ_{NF_{3}} = 0.24 D μ_{CHCl_{3}} = 1.01 D$ Hence dipole moment of $NF_{3} < HBr < H_{2} S < CHCl_{3}$

Stream:JEESubject:CHEM_REMOVEDTopic:CHEMICAL BONDINGSubtopic:Dipole Moment

⏱ 2mℹ️ Source: PYQ_2025

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