Which one of the following properties is not shown by NO ?

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TestHub · Accepted Answer

As per MOT, electronic configuration of NO is

$σ 1 s^{2} < \overset{*}{σ} 1 s^{2} < σ 2 s^{2} < \overset{*}{σ} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < \overset{*}{π} 2 p_{x}^{1} = \overset{*}{π} 2 p_{y}^{0}$

It is paramagnetic due to $π 2^{*} {py}^{1}$ (unpaired electron)

Bond order of NO $(i . e . O_{_{2}}^{+}) = \frac{10 - 5}{2} = 2.5$

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