Biology - Principles of Inheritance and Variation Question with Solution | TestHub

In a Mendelian dihybrid cross, the number of segregating gene pairs is $n=2$.

The number of phenotypes in the ${\text{F}}_2$ generation is given by the formula $2^n$.

Number of phenotypes = $2^2=4$.

The number of genotypes in the ${\text{F}}_2$ generation is given by the formula $3^n$.

Number of genotypes = $3^2=9$.

Thus, the number of phenotypes and genotypes are $4$ and $9$ respectively.

Answer: $4,9$