Biology - Principles of Inheritance and Variation Question with Solution | TestHub
BiologyPrinciples of Inheritance and VariationTest CrossMedium2 minPYQ_2026
BiologyMediumsingle choice
A pea plant with genotype RrYy is crossed with another pea plant with genotype rryy. What will be the number of phenotypes obtained by this cross?
Options:
Answer:
D
Solution:
The given cross is between a dihybrid plant (RrYy) and a homozygous recessive plant (rryy).
This is a dihybrid test cross.
The plant with genotype RrYy produces four types of gametes: RY, Ry, rY, and ry.
The plant with genotype rryy produces only one type of gamete: ry.
The offspring produced from this cross will have the following genotypes and phenotypes:
RrYy : Round Yellow
Rryy : Round Green
rrYy : Wrinkled Yellow
rryy : Wrinkled Green
Thus, four different phenotypes are obtained in a ratio of .
Answer:
Stream:MHT_CET_MEDICALSubject:BiologyTopic:Principles of Inheritance and VariationSubtopic:Test Cross
⏱ 2mℹ️ Source: PYQ_2026
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