Biology - Principles of Inheritance and Variation Question with Solution | TestHub

In a typical monohybrid cross, the $F_2$ generation genotypic ratio is $1:2:1$ for homozygous dominant, heterozygous, and homozygous recessive respectively.

The proportion of homozygous plants (both dominant and recessive) is $\frac{1+1}{4}=\frac{1}{2}$.

The proportion of heterozygous plants is $\frac{2}{4}=\frac{1}{2}$.

Given the total number of plants in the $F_2$ generation is $120$.

Number of homozygous plants = $\frac{1}{2}\times 120=60$.

Number of heterozygous plants = $\frac{1}{2}\times 120=60$.

Answer: 60 and 60.